NCERT Revision Notes for Chapter 5 Arithmetic Progressions Class 10 Maths
CBSE NCERT Revision Notes1
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Sequence: It is set of numbers following an order, or a definite rule.2
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We can find the nth term of an A.P by using Tn = a + (n-1)d
We can find the required term by putting the numeric value of n(no. of term) which we have to find from starting.
nth term from the end: l - (n-1)d where, l is the last term
The number occurring at nth place is denoted by Tn . The first term is T1 , second term is T2 and so on.
Common difference d = T n-1 - T n
Examples:-
3, 7, 11, 15,19………….
This is an arithmetic progression which starts from 3. The common difference between two consecutive terms is 4.
That is
7-3=4, 11-7=4, 15-11=4
So, this is an AP with first term as 3, and common difference 4.
Or, we can say the AP is
3, 3+4, 3+4+4=3+2×4, 3+4+4+4=3+3×4
That is 4 is added to each term to get the next term.
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4
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Sum of n term of an AP is
Here n is number of terms of AP, a is first term and l is last term of the AP. Here, d is the common difference.
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